20a^2-3=7a

Solution for 20a^2-3=7a equation:

20a^2-3=7a

We move all terms to the left:

20a^2-3-(7a)=0

a = 20; b = -7; c = -3;
Δ = b2-4ac
Δ = -72-4·20·(-3)
Δ = 289
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$a_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$a_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{289}=17$
$a_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-7)-17}{2*20}=\frac{-10}{40}
=-1/4
$
$a_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-7)+17}{2*20}=\frac{24}{40}
=3/5
$